\(\dfrac{1}{2}-\dfrac{1}{8}=\dfrac{8-2}{16}=\dfrac{6}{16}=\dfrac{3}{8}\)
\(\dfrac{1}{2}-\dfrac{1}{8}=\dfrac{4}{8}-\dfrac{1}{8}=\dfrac{4-1}{8}=\dfrac{3}{8}\)
Giải;
\(\dfrac{1}{2}-\dfrac{1}{8}=\dfrac{8}{16}-\dfrac{2}{16}=\dfrac{8-2}{16}=\dfrac{6}{16}=\dfrac{3}{8}\)
3/8 bạn nhé , mình chỉ cần quy đồng thôi