\(c,=\dfrac{3-2\sqrt{2}-4\sqrt{2}+5}{3\sqrt{2}-1+3}=\dfrac{8-6\sqrt{2}}{2+3\sqrt{2}}\\ =\dfrac{\left(8-6\sqrt{2}\right)\left(3\sqrt{2}-2\right)}{14}\\ =\dfrac{36\sqrt{2}-52}{14}=\dfrac{18\sqrt{2}-26}{7}\)
\(d,=\dfrac{\left(3+\sqrt{3}\right)\left(3-\sqrt{3}\right)-\left(4\sqrt{3}-2\right)}{5-\left(3+\sqrt{3}\right)}\\ =\dfrac{6-4\sqrt{3}+2}{2-\sqrt{3}}=\dfrac{\left(8-4\sqrt{3}\right)\left(2+\sqrt{3}\right)}{1}\\ =12\)
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