Ta có; \(\left(2x-3\right)\left(4x^2+6x+9\right)-\left(2x+1\right)\left(4x^2-2x+1\right)+2\left(x-5\right)\left(x+5\right)=2\cdot\left(x+2\right)^2\)
=>\(8x^3-27-8x^3-1+2\left(x^2-25\right)=2\left(x^2+4x+4\right)\)
=>\(-28+2x^2-50=2x^2+8x+8\)
=>8x+8=-78
=>8x=-86
=>\(x=-\frac{86}{8}=-\frac{43}{4}\)


