Question

Answer 1

\(\Rightarrow9\left(x-3\right)=6\left(2x-7\right)\\ \Rightarrow9x-27=12x-42\\ \Rightarrow3x=15\\ \Rightarrow x=5\)

Answer 2

Đề bài yêu cầu tìm x?

Answer 3

Ta có: \(\dfrac{6}{x-3}=\dfrac{9}{2x-7}\)

\(\Leftrightarrow12x-42=9x-27\)

\(\Leftrightarrow3x=15\)

hay x=5

Answer 4

6(2x-7)=9(x-3)

12x-42=9x-27

3x=15

x=5

Answer 5

\(\dfrac{6}{x-3}=\dfrac{9}{2x-7}< =>\dfrac{6\left(2x-7\right)}{\left(x-3\right)\left(2x-7\right)}=\dfrac{9\left(x-3\right)}{\left(x-3\right)\left(2x-7\right)}=>12x-42=9x-27< =>3x=15< =>x=5\)

Answer 6

\(\dfrac{6}{x-3}=\dfrac{9}{2x-7}\)

<=> \(\dfrac{6\left(2x-7\right)}{\left(x-3\right)\left(2x-7\right)}=\dfrac{9\left(x-3\right)}{\left(2x-7\right)\left(x-3\right)}\)

<=> 6(2x - 7) = 9(x - 3)

<=> 12x - 42 = 9x - 27

<=> 12x - 9x = 42 - 27

<=> 3x = 15

<=> x = 5

Answer 7

⇒9(x−3)

=>6(2x−7)

⇒9x−27

=>12x−42

⇒3x=15

⇒x=5
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