\(3=\sqrt{3^2}=\sqrt{9}>\sqrt{7}\Rightarrow3>\sqrt{7}\)
\(5=\sqrt{5^2}=\sqrt{25}>\sqrt{23}\Rightarrow5>\sqrt{23}\)
a) ta có : \(3=\sqrt{9}\) mà \(\sqrt{9}>\sqrt{7}\)
Suy ra \(3>\sqrt{7}\)
b) Ta có: \(5=\sqrt{25}\)mà \(\sqrt{23}< \sqrt{25}\)
suy ra : \(\sqrt{23}< 5\)
a/ 3 = \(\sqrt{9}\), 9 > 7 nên \(\sqrt{9}\) > \(\sqrt{7}\), vậy 3 > \(\sqrt{7}\)
b/ 5 = \(\sqrt{25}\), 23 < 25 nên \(\sqrt{23}\) < \(\sqrt{25}\), vậy \(\sqrt{23}\) < 5

