\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Rightarrow7\left(x-1\right)=6\left(x+5\right)\)
\(\Rightarrow7x-7=6x+30\)
\(\Rightarrow x=37\)
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
<=> \(\dfrac{7\left(x-1\right)}{7\left(x+5\right)}=\dfrac{6\left(x+5\right)}{7\left(x+5\right)}\)
<=> 7(x - 1) = 6(x + 5)
<=> 7x - 7 = 6x + 30
<=> 7x - 6x = 30 + 7
<=> x = 37
có : (x-1).7=(x+5).6 7x-7=6x+30 7x-6x=30+7 x=37
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Leftrightarrow7x-7=6x+30\)
hay x=37
