Lời giải:
$|x-\frac{1}{3}|=|2-3x|$
\(\Leftrightarrow \left[\begin{matrix} x-\frac{1}{3}=2-3x\\ x-\frac{1}{3}=3x-2\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x=\frac{7}{12}\\ x=\frac{5}{6}\end{matrix}\right.\)
Ta có: \(\left|x-\dfrac{1}{3}\right|=\left|3x-2\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=3x-2\\x-\dfrac{1}{3}=2-3x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-2x=-\dfrac{5}{3}\\4x=\dfrac{7}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{6}\\x=\dfrac{7}{12}\end{matrix}\right.\)
