\(\left(x-1\right)\left(2x+1\right)=\left(x-1\right)\left(x+3\right)\\ \Leftrightarrow2x^2-x-1-x^2-3x+x+3=0\\ \Leftrightarrow x^2-3x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=1\end{matrix}\right.\\ \Rightarrow S=\left\{1;2\right\}\)
=> Chọn A