Question

Answer 1

Từ giả thiết ta có:

\(\left\{{}\begin{matrix}\widehat{A}-\widehat{B}=10^o\\\widehat{A}+\widehat{B}=360^o-60^o-80^o=220^o\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}\widehat{A}=115^o\\\widehat{B}=105^o\end{matrix}\right.\)

Answer 2

Ta có: \(\widehat{A}+\widehat{B}=220^0\)

mà \(\widehat{A}-\widehat{B}=10^0\)

nên \(2\cdot\widehat{A}=230^0\)

\(\Leftrightarrow\widehat{A}=115^0\)

\(\Leftrightarrow\widehat{B}=105^0\)

Answer 3

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