Question

Answer 1

Em chỉ cần mỗi đáp án thôi ạ,ko cần giải chi tiết quá đâu

Answer 2

3. \(\sqrt{4x^2-4x+4}=7x-11\)

<=> \(\sqrt{\left(2x-2\right)^2}=7x-11\)

<=> 2x - 2 = 7x - 11

<=> 11 - 2 = 7x - 2x

<=> 5x = 9

<=> x = \(\dfrac{9}{5}\)

Answer 3

2. \(\dfrac{1}{5}\sqrt{25x+50}-5\sqrt{x+2}+\sqrt{9x+18}+9=0\)

<=> \(\sqrt{25x+50}-\sqrt{x+2}+\sqrt{9x+18}=-9:5:\dfrac{1}{5}\)

<=> \(\sqrt{25x+50-x+2+9x+18}=-9\)

<=> C₁: 25x + 50 - x + 2 + 9x + 18 = 81

<=> 25x - x + 9x = 81 - 50 - 2 - 18

<=> 33x = 11

<=> x = \(\dfrac{1}{3}\)

C₂: \(\sqrt{25x+50-x+2+9x+18}=\sqrt{81}\)

<=> 25x + 50 - x + 2 + 9x + 18 = 81

Giải tiếp như C₁

Answer 4

1, \(\left(2\sqrt{x}+3\right)\left(2\sqrt{x}-1\right)-\sqrt{x}\left(-3+4\sqrt{x}\right)=0\)

<=>\(4x-2\sqrt{x}+6\sqrt{x}-3+3\sqrt{x}-4x=0\)

<=>\(7\sqrt{x}=3\)

<=>\(\sqrt{x}=\dfrac{3}{7}\)

<=>\(x=\dfrac{9}{49}\)

2) \(\dfrac{1}{5}\sqrt{25x+50}-5\sqrt{x+2}+\sqrt{9x+18}+9=0\)

<=>\(\sqrt{x+2}-5\sqrt{x+2}+3\sqrt{x+2}=-9\)

<=>\(-\sqrt{x+2}=-9\)

<=>\(\sqrt{x+2}=9\)

<=>\(x+2=81\)

<=>\(x=79\)

3) \(\sqrt{4x^2-4x+4}=7x-11\)

<=>\(4x^2-4x+4=49x^2-154x+121\)

<=>\(-45x^2+150x-117=0\)

<=>\(x=\dfrac{25+2\sqrt{10}}{15}\) hoặc \(x=\dfrac{25-2\sqrt{10}}{15}\)

 

Answer 5

1 mik đang tìm cách giải nha