Bài 3:
ta có: \(P=\left(m+2\right)\left(m^2-2m+4\right)-m^3+\left(m+3\right)\left(m-3\right)-m^2-18\)
\(=m^3+8-m^3+m^2-9-m^2-18\)
=-19
Bài 1:
a. (x + 3)(x - 1) - x(x - 5) = 11
<=> x2 - x + 3x - 3 - x2 + 5x = 11
<=> x2 - x2 - x + 3x + 5x = 11 + 3
<=> 7x = 14
<=> x = 2
Bài 4:
a. M = (2n + b)2 - (b - 2n)2
M = (4n2 + 4nb + b2) - (b2 - 4nb + 4n2)
M = 4n2 + 4nb + b2 - b2 + 4nb - 4n2
M = 4n2 - 4n2 + 4nb + 4nb + b2 - b2
M = 8nb


