a) \(x\left(5-3x\right)+3x\left(x-3\right)=16\)
\(\Rightarrow5x-3x^2+2x^2-9x=16\)
\(\Rightarrow-4x=16\Rightarrow x=-4\)
b) \(3x\left(x-10\right)=x-10\)
\(\Rightarrow3x\left(x-10\right)-\left(x-10\right)=0\)
\(\Rightarrow\left(x-10\right)\left(3x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=10\\x=\dfrac{1}{3}\end{matrix}\right.\)
a: ta có: \(x\left(5-3x\right)+3x\left(x-3\right)=16\)
\(\Leftrightarrow5x-3x^2+3x^2-9x=16\)
\(\Leftrightarrow-4x=16\)
hay x=-4
b: Ta có: \(3x\left(x-10\right)=x-10\)
\(\Leftrightarrow\left(x-10\right)\left(3x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=\dfrac{1}{3}\end{matrix}\right.\)
