\(\dfrac{1-2cos^2\alpha}{1+2sin\alpha.cos\alpha}=\dfrac{sin^2\alpha+cos^2\alpha-2cos^2\alpha}{sin^2\alpha+2sin\alpha.cos\alpha+cos^2\alpha}=\dfrac{sin^2\alpha-cos^2\alpha}{\left(sin\alpha+cos\alpha\right)^2}=\dfrac{\left(sin\alpha-cos\alpha\right)\left(sin\alpha+cos\alpha\right)}{\left(sin\alpha+cos\alpha\right)^2}=\dfrac{sin\alpha-cos\alpha}{sin\alpha+cos\alpha}\)

