a: Ta có: \(2x-1=0\)
\(\Leftrightarrow2x=1\)
hay \(x=\dfrac{1}{2}\)
b: Ta có: \(\left(4x-1\right)\left(3x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{4}{3}\end{matrix}\right.\)
c: Ta có: \(\left|2x-1\right|-4=0\)
\(\Leftrightarrow\left|2x-1\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=4\\2x-1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=5\\2x=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)