Question

Answer 1

Ta có: \(\left|x-2\right|-\left|1-2x\right|=0\)

\(\Leftrightarrow\left|x-2\right|=\left|2x-1\right|\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=x-2\\2x-1=2-x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\3x=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=1\end{matrix}\right.\)

Answer 2

`7//|x-2|-|1-2x|=0`

`<=>|x-2|=|1-2x|`

`<=>[(x-2=1-2x),(x-2=2x-1):}`

`<=>[(3x=3),(x=-1):}`

`<=>[(x=1),(x=-1):}`

Vậy `x=1` hoặc `x=-1`