Question

Answer 1

`b)Q=((5-2sqrt5)/(2-sqrt5)-2)((5+3sqrt5)/(3+sqrt5)-2)`

`Q=((sqrt5(sqrt5-2))/(2-sqrt5)-2)((sqrt5(sqrt5+3))/(3+sqrt5)-2)`

`Q=(-sqrt5-2)(sqrt5-2)`

`Q=-(sqrt5+2)(sqrt5-2)=-(5-2)=-3`

Answer 2

\(Q=\dfrac{5-2\sqrt{5}-2\left(2-\sqrt{5}\right)}{2-\sqrt{5}}.\dfrac{5+3\sqrt{5}-2\left(3+\sqrt{5}\right)}{3+\sqrt{5}}\\ =\dfrac{1}{2-\sqrt{5}}.\dfrac{\sqrt{5}-1}{3+\sqrt{5}}=\dfrac{\sqrt{5}-1}{\left(2-\sqrt{5}\right)\left(3+\sqrt{5}\right)}=\dfrac{\sqrt{5}-1}{1-\sqrt{5}}=-1\)

tick mik nha