Question

Answer 1

a) \(\dfrac{7}{5}-\dfrac{a}{4}=\dfrac{13}{20}\)

\(\Rightarrow\dfrac{a}{4}=\dfrac{7}{5}-\dfrac{13}{20}=\dfrac{28}{20}-\dfrac{13}{20}=\dfrac{3}{4}\)

\(\Rightarrow a=3\)

b) \(\dfrac{2}{5}+\dfrac{a}{3}=\dfrac{26}{15}\)

\(\Rightarrow\dfrac{a}{3}=\dfrac{26}{15}-\dfrac{2}{5}=\dfrac{26}{15}-\dfrac{6}{15}=\dfrac{4}{3}\)

\(\Rightarrow a=4\)

Answer 2

a)\(\dfrac{7}{5}-\dfrac{a}{4}=\dfrac{13}{20}\)

\(\Rightarrow\)\(\dfrac{a}{4}=\dfrac{7}{5}-\dfrac{13}{20}\)

\(\Rightarrow\)\(\dfrac{a}{4}=\dfrac{3}{4}\)

\(\Rightarrow\)\(a=3\)

b)\(\dfrac{2}{5}+\dfrac{a}{3}=\dfrac{26}{15}\)

\(\Rightarrow\)\(\dfrac{a}{3}=\dfrac{26}{15}-\dfrac{2}{5}\)

\(\Rightarrow\)\(\dfrac{a}{3}=\dfrac{4}{3}\)

\(\Rightarrow\)\(a=4\)

Answer 3

a: Ta có: \(\dfrac{7}{5}-\dfrac{1}{4}a=\dfrac{13}{20}\)

\(\Leftrightarrow a\cdot\dfrac{1}{4}=\dfrac{7}{5}-\dfrac{13}{20}=\dfrac{3}{4}\)

hay a=3

b:Ta có: \(\dfrac{2}{5}+\dfrac{1}{3}a=\dfrac{26}{15}\)

\(\Leftrightarrow a\cdot\dfrac{1}{3}=\dfrac{4}{3}\)

hay a=4