a: Ta có: xy//BC
=>\(\hat{xAB}=\hat{ABC}\) (hai góc so le trong)
=>\(\hat{xAB}=40^0\)
Ta có: Ay//BC
=>\(\hat{yAC}=\hat{ACB}\) (hai góc so le trong)
=>\(\hat{yAC}=50^0\)
b: Ta có; \(\hat{xAB}+\hat{BAC}+\hat{CAy}=180^0\)
=>\(\hat{BAC}=180^0-40^0-50^0=90^0\)
c: ΔHAC vuông tại H
=>\(\hat{HAC}+\hat{HCA}=90^0\)
=>\(\hat{HAC}=90^0-50^0=40^0\)
