ĐKXĐ: \(x\ge\dfrac{5}{2}\)
\(\sqrt{x+1}+\sqrt{2x-5}=\sqrt{x+6}\)
\(\Leftrightarrow3x-2+2\sqrt{\left(x+1\right)\left(2x-5\right)}=x+6\)
\(\Leftrightarrow\sqrt{2x^2-3x-5}=4-x\) (\(x\le4\))
\(\Rightarrow2x^2-3x-5=x^2-8x+16\)
\(\Leftrightarrow x^2+5x-21=0\Rightarrow\left[{}\begin{matrix}x=\dfrac{-5+\sqrt{109}}{2}\\x=\dfrac{-5-\sqrt{109}}{2}\left(loại\right)\end{matrix}\right.\)

