e: \(\frac{2\left(1-3x\right)}{5}-\frac{3x+2}{10}=4-\frac{3\left(2x+1\right)}{4}\)
=>\(\frac{8\left(1-3x\right)}{20}-\frac{2\left(3x+2\right)}{20}=\frac{80}{20}-\frac{15\left(2x+1\right)}{20}\)
=>8(1-3x)-2(3x+2)=80-15(2x+1)
=>8-24x-6x-4=80-30x-15
=>-30x+4=-30x+65
=>4=65(vô lý)
=>x∈∅
e: \(\frac{3x+2}{2}-\frac{3x+1}{6}=2x+\frac53\)
=>\(\frac{3\left(3x+2\right)}{6}-\frac{3x+1}{6}=\frac{12x}{6}+\frac{10}{6}\)
=>3(3x+2)-3x-1=12x+10
=>9x+6-3x-1=12x+10
=>12x+10=6x+5
=>6x=-5
=>x=-5/6
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