Bài 2:
a) Ta có: \(x-2\left(x+1\right)>17x+4\left(x-6\right)\)
\(\Leftrightarrow x-2x-2>17x+4x-24\)
\(\Leftrightarrow-x-2>21x-24\)
\(\Leftrightarrow-x-21x>-24+2\)
\(\Leftrightarrow-22x>-22\)
hay x<1
b) Ta có: \(\dfrac{12x+1}{12}\ge\dfrac{9x+3}{3}-\dfrac{8x+1}{4}\)
\(\Leftrightarrow\dfrac{12x+12}{12}\ge\dfrac{36x+12}{12}-\dfrac{24x+3}{12}\)
\(\Leftrightarrow12x+12\ge36x+12-24x-3\)
\(\Leftrightarrow12\ge9\)(luôn đúng)
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