Question

Answer 1

Answer 2

a) Ta có: \(15\dfrac{1}{4}:\left(-\dfrac{2}{3}\right)+\dfrac{-1}{2}+4\dfrac{3}{4}:\left(-\dfrac{2}{3}\right)\)

\(=\dfrac{61}{4}\cdot\dfrac{-3}{2}+\dfrac{19}{4}\cdot\dfrac{-3}{2}+\dfrac{-1}{2}\)

\(=\dfrac{-3}{2}\cdot20+\dfrac{-1}{2}\)

\(=-30+\dfrac{-1}{2}\)

\(=\dfrac{-61}{2}\)

b) Ta có: \(\dfrac{1}{3}-2\cdot\left(\dfrac{-1}{2}\right)^3+\dfrac{7}{6}\)

\(=\dfrac{1}{3}-2\cdot\dfrac{-1}{8}+\dfrac{7}{6}\)

\(=\dfrac{2}{6}+\dfrac{7}{6}+\dfrac{1}{4}\)

\(=\dfrac{3}{2}+\dfrac{1}{4}=\dfrac{7}{4}\)