c, `15/24-3/8-1/6`
`=15/24-9/24-4/24`
`=2/24=1/12`
c, `25 : 5/11`
`=25 xx 11/5`
`= 55`
d,
`x xx x = 4/9`
`=>x^2=4/9`
`=>x=\pm 2/3`
Vậy `x=\pm 2/3`
c) \(\dfrac{15}{24}-\dfrac{3}{8}-\dfrac{1}{6}=\dfrac{5}{8}-\dfrac{2}{8}-\dfrac{1}{6}=\dfrac{1}{4}-\dfrac{1}{6}=\dfrac{1}{12}\)\(\dfrac{15}{24}-\dfrac{3}{8}-\dfrac{1}{6}=\dfrac{5}{8}-\dfrac{3}{8}-\dfrac{1}{6}=\dfrac{1}{4}-\dfrac{1}{6}=\dfrac{3}{12}-\dfrac{2}{12}=\dfrac{12}{ }\)
c) \(25:\dfrac{5}{11}=25\cdot\dfrac{11}{5}=55\)
d) \(x^2=\dfrac{4}{9}\Leftrightarrow x\in\left\{\dfrac{2}{3};-\dfrac{2}{3}\right\}\)
c. \(\dfrac{15}{24}-\dfrac{3}{8}-\dfrac{1}{6}=\dfrac{15}{24}-\dfrac{9}{24}-\dfrac{4}{24}=\dfrac{1}{12}\)
c. \(25:\dfrac{5}{11}=\dfrac{25.11}{5}=55\)
d. \(x.x=\dfrac{4}{9}\Leftrightarrow x^2=\dfrac{4}{9}\Leftrightarrow x=\dfrac{2}{3}\)