a) Thay x=-4 vào B, ta được:
\(B=\dfrac{1-2\cdot\left(-4\right)}{2-\left(-4\right)}=\dfrac{1+8}{2+4}=\dfrac{9}{6}=\dfrac{3}{2}\)
b) Ta có: \(A=\dfrac{2-x}{2+x}-\dfrac{16}{4-x^2}-\dfrac{2+x}{2-x}\)
\(=\dfrac{x^2-4x+4-16-x^2-4x-4}{\left(2+x\right)\left(2-x\right)}\)
\(=\dfrac{-8x-16}{\left(2+x\right)\left(2-x\right)}\)
\(=\dfrac{8}{x-2}\)