Bài 2:
a) Ta có: \(\dfrac{3}{5}-x=\dfrac{8}{9}\)
\(\Leftrightarrow x=\dfrac{3}{5}-\dfrac{8}{9}=\dfrac{27}{45}-\dfrac{40}{45}\)
hay \(x=\dfrac{-13}{45}\)
b) Ta có: \(\dfrac{2}{5}:\left(2x+\dfrac{3}{4}\right)=\dfrac{8}{25}\)
\(\Leftrightarrow2x+\dfrac{3}{4}=\dfrac{2}{5}:\dfrac{8}{25}=\dfrac{2}{5}\cdot\dfrac{25}{8}=\dfrac{5}{4}\)
\(\Leftrightarrow2x=\dfrac{1}{2}\)
hay \(x=\dfrac{1}{4}\)