Bài 1:
a: 11+(-12)-(-10)
=11-12+10
=21-12
=9
b: \(25\cdot67-\left(-37\right)\cdot25+25\cdot\left(-4\right)\)
\(=25\cdot67+25\cdot37-25\cdot4\)
\(=25\cdot\left(67+37-4\right)=25\cdot100=2500\)
c: \(7^6:7^4+2^3\cdot2^2-225^2:15^3\)
\(=7^2+2^5-15^4:15^3\)
=49+32-15
=49+17
=66
d: \(\left(-5-3\right)\left(3-5\right):\left(-3+5\right)\)
\(=\left(-8\right)\cdot\left(-2\right):2\)
\(=16:2=8\)
e: \(4\cdot\left(13-16\right)-\left(3-5\right)\cdot\left(-3\right)^2\)
\(=4\cdot\left(-3\right)-\left(-2\right)\cdot9\)
=-12+18
=6
f: \(235-\left(34+135\right)-10\)
=235-135-34-10
=100-44
=56
Bài 2:
\(A=49\frac{8}{23}-\left(5\frac{7}{32}-14\frac{15}{23}\right)\)
\(=49+\frac{8}{23}-5-\frac{7}{32}+14+\frac{15}{23}\)
\(=\left(49-5+14\right)+1-\frac{7}{32}=59-\frac{7}{32}=\frac{1881}{32}\)
\(B=\left(19\frac58:\frac{7}{12}-13\frac14:\frac{7}{12}\right)\cdot\frac45\)
\(=\left(19+\frac58-13-\frac14\right):\frac{7}{12}\cdot\frac45\)
\(=\left(6+\frac38\right)\cdot\frac{12}{7}\cdot\frac45=\frac{51}{8}\cdot\frac{48}{35}=\frac{51}{1}\cdot\frac{6}{35}=\frac{306}{35}\)
\(C=9\frac{5}{13}-\left(\frac25+4\frac{5}{13}\right)\)
\(=9+\frac{5}{13}-\frac25-4-\frac{5}{13}\)
\(=5-\frac25=\frac{23}{5}\)
\(D=\frac23-0,25:\frac34+\frac58\cdot\left(-2\right)^2\)
\(=\frac23-\frac14\cdot\frac43+\frac58\cdot4\)
\(=\frac23-\frac13+\frac52=\frac13+\frac52=\frac{2+15}{6}=\frac{17}{6}\)
\(E=\left(\frac25\right)^2+5\frac12\cdot\left(4,5-2\right)+\frac{2^3}{-4}\)
\(=\frac{4}{25}+\frac{11}{2}\cdot2,5+\frac{8}{-4}\)
\(=\frac{4}{25}+\frac{11}{2}\cdot\frac52-2=\frac{4}{25}+\frac{55}{4}-2=\frac{16+1375-200}{100}=\frac{1191}{100}\)
\(F=\left(-\frac12\right)^2:\frac14-2\cdot\left(-\frac12\right)^2\)
\(=\frac14\cdot4-2\cdot\frac14\)
\(=1-\frac12=\frac12\)
\(G=\left(6-2\frac45\right)\cdot3\frac18+1\frac38:\frac14\)
\(=\left(6-2-\frac45\right)\cdot\frac{25}{8}+\frac{11}{8}\cdot4\)
\(=\left(4-\frac45\right)\cdot\frac{25}{8}+\frac{11}{2}=\frac{16}{5}\cdot\frac{25}{8}+\frac{11}{2}=5\cdot2+\frac{11}{2}=10+\frac{11}{2}=15,5\)
\(H=\left(-2\right)^3\cdot\frac{-1}{4}+\left(\frac43-1\frac56\right):\frac{5}{12}\)
\(=-8\cdot\frac{-1}{4}+\left(\frac43-\frac{11}{6}\right)\cdot\frac{12}{5}\)
\(=2+\frac{-3}{6}\cdot\frac{12}{5}=2+\frac{-36}{30}=2-\frac65=\frac45\)
\(I=\left(3-2\frac13+\frac14\right):\left(4-5\frac16+2\frac14\right)\)
\(=\left(3-2-\frac13+\frac14\right):\left(4-5-\frac16+2+\frac14\right)\)
\(=\left(1-\frac13+\frac14\right):\left(1-\frac16+\frac14\right)=\frac{12-4+3}{12}:\frac{12-2+3}{12}=\frac{11}{13}\)
\(K=125\%\cdot\left(-\frac12\right)^2:\left(1\frac{5}{16}-1,5\right)+2018^0\)
\(=\frac54\cdot\frac14:\left(\frac{21}{16}-\frac{24}{16}\right)+1\)
\(=\frac{5}{16}\cdot\frac{16}{-3}+1=-\frac53+1=-\frac23\)
