a) Ta có: \(A=\dfrac{2^2}{1\cdot3}\cdot\dfrac{3^2}{2\cdot4}\cdot\dfrac{4^2}{3\cdot5}\cdot...\cdot\dfrac{20^2}{19\cdot21}\)
\(=\dfrac{2\cdot3\cdot4\cdot...\cdot20}{1\cdot2\cdot3\cdot...\cdot20}\cdot\dfrac{2\cdot3\cdot4\cdot...\cdot20}{3\cdot4\cdot...\cdot21}\)
\(=2\cdot\dfrac{40}{21}=\dfrac{80}{21}\)