Bài 4:
Ta có: \(1\dfrac{13}{15}\cdot\left(0.5\right)^2\cdot3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{4}\cdot3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\dfrac{-47}{60}\cdot\dfrac{24}{47}\)
\(=\dfrac{7}{5}+\dfrac{-2}{5}=1\)
Bài 5:
Ta có: \(B=\left(\dfrac{151515}{161616}+\dfrac{17^9}{17^{10}}\right)-\left(\dfrac{1500}{1600}-\dfrac{176}{187}\right)\)
\(=\dfrac{15}{16}+\dfrac{1}{17}-\dfrac{15}{16}+\dfrac{16}{17}\)
=1
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