a) 22 - 4,37 + 34 - 1,63
= (22 + 34) - (4,37 + 1,63)
= 56 - 6
= 50
b) (13 - 18)3 + (- 4,25) : 25
= (- 5)3 + (- 0,17)
= - 125 - 0,17
= - 125,17
c) 8\(\dfrac{2}{9}\) - (4\(\dfrac{2}{9}\) - 5\(\dfrac{1}{2}\))
= 8\(\dfrac{2}{9}\) - 4\(\dfrac{2}{9}\) + 5\(\dfrac{1}{2}\))
= 4 + 5\(\dfrac{1}{2}\)
= 9\(\dfrac{1}{2}\)
d) 7\(\dfrac{5}{12}\) - (\(\dfrac{7}{16}-\dfrac{1}{12}\))
= 7\(\dfrac{5}{12}\) + \(\dfrac{1}{12}\) - \(\dfrac{7}{16}\)
= \(7\dfrac{1}{2}\) - \(\dfrac{7}{16}\)
= \(\dfrac{15}{2}-\dfrac{7}{16}\) = \(\dfrac{120}{16}-\dfrac{7}{16}=\dfrac{113}{16}\)
e) 1\(\dfrac{2}{5}\) . \(\dfrac{3}{4}\) + \(\dfrac{3}{5}\) . |- 0,75|
= \(\dfrac{7}{5}.\dfrac{3}{4}+\dfrac{3}{5}.\dfrac{3}{4}\)
= \(\dfrac{3}{4}.\left(\dfrac{7}{5}+\dfrac{3}{5}\right)\)
= \(\dfrac{3}{4}.2=\dfrac{3}{2}\)
a) Ta có: \(22-4.37+34-1.63\)
\(=\left(22+34\right)-\left(4.37+1.63\right)\)
=56-6
=50
b) Ta có: \(\left(13-10\right)^3+\left(-4.25\right):25\)
=-125-0.17
=-125,17
