c) Ta có: \(C=\left(x+2\right)\left(x-3\right)-\left(x+3\right)\left(x-4\right)\)
\(=x^2-3x+2x-6-\left(x^2-4x+3x-12\right)\)
\(=x^2-x-6-x^2+x+12\)
=6
d) Ta có: \(D=\left(3x+1\right)\left(2x+3\right)-x\left(6x+11\right)-7\)
\(=6x^2+9x+2x+3-6x^2-11x-7\)
=-4


