Question

Answer 1

\(\left(3x-1\right)\left(x^2+2\right)+\left(7x-10\right)\left(9x^2-1\right)\\ =3x^3+6x-x^2-2+63x^3-7x-90x^2+10\\ =66x^3-x-91x^2+8\)

Answer 2

đề bài là j vậy?

Answer 3

Ta có: \(\left(3x-1\right)\left(x^2+2\right)+\left(7x-10\right)\left(9x^2-1\right)\)

\(=3x^3+6x-x^2-2+63x^3-7x-90x^2+10\)

\(=66x^3-91x^2-x+8\)