\(y=\frac{4}{3}-\frac{1}{3072}=\frac{4096}{3072}+\frac{1}{3072}=\frac{4096+1}{3072}=\frac{4097}{3072}\)
\(y=\frac{4}{3}-\frac{1}{3072}=\frac{4096-1}{3072}=\frac{4095}{3072}=\frac{1365}{1024}\)
\(y=\frac{4}{3}-\frac{1}{3072}=\frac{4096}{3072}-\frac{1}{3072}=\frac{4096-1}{3072}=\frac{4095}{3072}\)