Question

(y+1)+(y+4)+(y+7)+(y+10)+......+(y+31)=231

Nhanh nha

Answer 1

\(\left(y+1\right)+\left(y+4\right)+\left(y+7\right)+....+\left(y+31\right)=231\)

\(\Rightarrow\left(y+y+...+y\right)+\left(1+4+7+...+31\right)=231\)

\(\Rightarrow11y+176=231\)

\(\Rightarrow11y=231-176\)

\(\Rightarrow11y=55\)

\(\Rightarrow y=55:11\)

\(\Rightarrow y=5\)

Vậy y = 5

Answer 2

(y+1)+(y+4)+(y+7)+..........+(y+31)=231

y+1+y+4+y+7+y+10+..........+y+31=231

(y+y+y+y+........+y+y)+(1+4+7+10+....+31)=231

y*11+176=231

y*11=231-176

y*11=55

y=55 :11

y=5

vậy y=5

Answer 3

Cảm ơn nha