\(y:\frac{1}{4}+y:\frac{1}{8}-y:\frac{1}{2}=10\)
\(\Leftrightarrow y.4+y.8-y.2=10\)
\(\Leftrightarrow y.\left(8+4-2\right)=10\)
\(\Leftrightarrow10y=10\)
\(\Leftrightarrow y=10:10=1\)
Vậy y=1
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\(y\div\frac{1}{4}+y\div\frac{1}{8}-y\div\frac{1}{2}=10\)
\(y\times4+y\times8-y\times2=10\)
\(4y+8y-2y=10\)
\(10y=10\)
\(y=1\)