Question

(y-3)^2014+|2x+1|^2015=0

Answer 1

vì ( y - 3 )²⁰¹⁴ \(\ge\)0 \(\forall\)y

| 2x + 1 |²⁰¹⁵ \(\ge\)0 \(\forall\)x

\(\Rightarrow\)( y - 3 )²⁰¹⁴ + | 2x + 1 |²⁰¹⁵ \(\ge\)0 \(\forall\)x,y

Mà ( y - 3 )²⁰¹⁴ + | 2x + 1 |²⁰¹⁵ = 0

\(\Rightarrow\hept{\begin{cases}\left(y-3\right)^{2014}=0\\\left|2x+1\right|^{2015}=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}y-3=0\\2x+1=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}y=3\\x=\frac{-1}{2}\end{cases}}\)