x/y=3
=> x=3y
x+y=-6/5
=> 3y+y=-6/5
=> 4y=-6/5
=> y=-3/10
=> x=3y=3.(-3/10)=-9/10
=> 10x=10.(-9/10)=-9
Ta có: x+y=-6/5
Thay x=3y, ta được:
3y+y=\(-\frac{6}{5}\)
\(\Rightarrow4y=\frac{-6}{5}\)
\(y=\frac{-3}{10}\)
\(\Rightarrow x=\frac{-6}{5}-\frac{-3}{10}\)
\(\Rightarrow x=\frac{-9}{10}\)
\(\Rightarrow10x=\frac{-9}{10}.10=-9\)