\(x\left(x+7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-7\end{cases}}}\)
x.(x+7)=0
\(\Rightarrow\)x=0 hoặc x+7=0
\(\Rightarrow\)x=0+7=7
x {x - 7 } {x- 3 }=0
x=0; x-7 = 0 ;x-3 = 0
vậy x=0;x=7;x=3
đúng ko các bn
tim x
(x+7)*(x-3)<0
(x+7)*(x-3)>0
(x+7)*(x-3)=0
tìm x
x.(x+7)=0
(x+12).(x-3)=0
(-x+5).(3-x)=0
x.(2+x).(7-x)=0
(x-1).(x+2).(-x-3)=0
Tìm x :
1) -12 + 3 . ( -x +7 ) = -18
2) x . ( x + 7 ) = 0
3) ( -x + 5 ) . ( 3 - x ) = 0
4) ( x + 12 ) . ( x - 3 ) = 0
5) x . ( 2 + x ) . ( 7 - x ) = 0
6) ( x - 1 ) . ( x + 2 ) . ( -x - 3 ) = 0
Tìm x
1. x(x+7)=0
2. (x+12)(x-3)=0
3. (-x+5)(3-x)=0
4. x(2+x)(7-x)=0
5. (x-1)(x+2)(-x-3)=0
tìm x
1/ x.(x+7)=0
2/ (x+12).(x-3)=0
3/ (-x+5).(3-x)=0
4/ x.(2+x).(7-x)=0
5/ (x-1).(x+2).(-x-3)=0
Tìm x:
a) x.x+7)=0
b) (x+12).(x-3)=0
c) (-5+5).(3-x)=0
d)x.(2+x).(7-x)=0
e) (x-1).(x-2).(-x-3)=0
bài 1: Tìm x
x.(x+7)=0
(x+12).(x-3)=0
(-x+5).(3-x)=0
x.(2+x).(7-x)=0
(x-1).(x+2).(-x-3)=0(làm đc 2 like)
x(x+7)=0
(x+12).(x-3)=0
(-x+5).(3-x)=0
x(2+x).(7-x)=0
(x-1.(x-2).(-x-3)=0
x.(x+7)=0 (x+12).(x-3)=0
(-x+5).(3-x)=0 x.(2+x).(7-x)=0
(x-1).(x+2).(-x-3)=0 Mn giải giúp tui nha
