x ( x + 3 ) = x2 + 6
=> x2 + 3x = x2 + 6
=> x2 + 3x - x2 = 6
=> 3x = 6
=> x = 2
Ta có : 2x - 36 = 48
=> 2x = 48 + 36
=> 2x = 84
=> x = 84 : 2
=> x = 42
x(x+3)=x2 +6
<=>x2+3x=x2+6
<=>x2+3x-x2+6=0
<=>(x2-x2)+3x+6=0
<=>0+3x+6=0
<=>3x=-6
<=>x=-2
x ( x + 3 ) = x2 + 6
= > x2 + 3x = x2 + 6
=> x2 - x2 + 3x = 6
=> 3x = 6
=> x = 2
Kay Phạm-_- bạn đúng nhầm người rồi nó copy tui mà với lại nó sai
x(x+3)=x2 +6
<=>x2+3x=x2+6
<=>x2+3x-x2+6=0
<=>(x2-x2)+3x+6=0
<=>0+3x+6=0
<=>3x=-6
<=>x=-2
x(x+3)=x2 +6
<=>x2+3x=x2+6
<=>x2+3x-x2+6=0
<=>(x2-x2)+3x+6=0
<=>0+3x+6=0
<=>3x=-6
<=>x=-2
Ta có :
x(x+3)=x2 +6
<=>x2+3x=x2+6
<=>x2+3x-x2+6=0
<=>(x2-x2)+3x+6=0
<=>0+3x+6=0
<=>3x=-6
<=>x=-2
Ta có :
x(x+3)=x2 +6
<=>x2+3x=x2+6
<=>x2+3x-x2+6=0
<=>(x2-x2)+3x+6=0
<=>0+3x+6=0
<=>3x=-6
<=>x=-2