x+(x+1)+(x+2)+(x+3)+...(x+2003)=2004
Tìm x, biết: x + (x+1) +(x+2) +...+(x+2003)=2004
x+(x+1)+(x+2)+...+(x+2003)=2004 tim x biet
Tìm x biết, (x-1)/ 2004 + (x-2)/ 2003 - (x-1) / 2002= (x-4)/ 2001
x-1/2004+x-2/2003-x-3/2002=x-4/2001
x+3/2003+x+2/2004+x+1/2005=-3
Tìm x: a, \(\frac{x-2004}{2003}+\frac{x-2003}{2004}+\frac{x-2005}{2004}=3+\frac{2005}{2003}\)\(+\frac{2004}{2005}\)
Tìm x biết: (x-1/2004)+(x-2/2003)-(x-3/2002)=x-4/2001
tìm x : x-1/2004+x-2/2003=x-3/2002+x-4/2001