Question

x(x-2 )-4x+8=0

Answer 1

\(x.\left(x-2\right)-4x+8=0\)

\(\Leftrightarrow x.\left(x-2\right)-4.\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-4\right).\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)

Vậy ....

Answer 2

x(x-2)-4(x-2)=0

x-2=0 hay x-4=0 

x=2          x=4