Question

x.(x-2) > 0

x^2-5x=0

2 caau de . lam nhanh tk luon

Answer 1

a) Ta có: 

\(x\left(x-2\right)>0\)

\(\Rightarrow\)\(\hept{\begin{cases}x< 0\\x-2< 0\end{cases}}\)hoặc \(\hept{\begin{cases}x>0\\x-2>0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x< 0\\x< 2\end{cases}}\)hoặc \(\hept{\begin{cases}x>0\\x>2\end{cases}}\)

\(\Rightarrow x< 0\)hoặc \(x>2\)thì x(x-2) >0.

b) \(x^2-5x=0\Rightarrow x\left(x-5\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-5=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=5\end{cases}}\)

Answer 2

chuc mung nguoi nhanh nhat .^^