Câu hỏi của Emily

Question

x(x-1)(x+1)-(x+1)(x^2-x+1)=0

Nguyễn Hoàng Minh · Accepted Answer

$\Leftrightarrow\left(x+1\right)\left(x^2-x-x^2+x-1\right)=0\
\Leftrightarrow x+1=0\
\Leftrightarrow x=-1$Câu trả lời: $\Leftrightarrow\left(x+1\right)\left(x^2-x-x^2+x-1\right)=0\
\Leftrightarrow x+1=0\
\Leftrightarrow x=-1$

Lấp La Lấp Lánh · Answer

$\Rightarrow x\left(x^2-1\right)-\left(x^3+1\right)=0$$\Rightarrow x^3-x-x^3-1=0\Rightarrow x+1=0\Rightarrow x=-1$Câu trả lời: $\Rightarrow x\left(x^2-1\right)-\left(x^3+1\right)=0$$\Rightarrow x^3-x-x^3-1=0\Rightarrow x+1=0\Rightarrow x=-1$

Duy Mạnh · Answer

a.x(x−1)(x+1)−(x+1)(x2−x+1)x(x−1)(x+1)−(x+1)(x2−x+1)=x(x2−1)−(x3+1)=x(x2−1)−(x3+1)=x3−x−x3−1=x3−x−x3−1=−x−1Câu trả lời: a.x(x−1)(x+1)−(x+1)(x2−x+1)x(x−1)(x+1)−(x+1)(x2−x+1)=x(x2−1)−(x3+1)=x(x2−1)−(x3+1)=x3−x−x3−1=x3−x−x3−1=−x−1

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