\(\dfrac{x}{x-1}-\dfrac{3}{x-1}=\dfrac{2x-1}{x^2-1}\)
\(ĐK:x\ne\pm1\)
\(\Leftrightarrow\dfrac{\left(x-3\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}=\dfrac{2x-1}{\left(x-1\right)\left(x+1\right)}\)
\(\Leftrightarrow\left(x-3\right)\left(x+1\right)=2x-1\)
\(\Leftrightarrow x^2+x-3x-3-2x+1=0\)
\(\Leftrightarrow x^2-4x-2=0\)
( Ngiệm xấu lắm bạn!! )