Question

xin sự giúp đỡ 

Answer 1

Ta có: \(R=p\dfrac{l}{S}=0,40\cdot10^{-6}\dfrac{20}{0,1\cdot10^{-6}}=80\Omega\)

\(=>I=\dfrac{U}{R}=\dfrac{24}{80}=0,3A\)