x+\(\frac{3}{2}\)=2
x = 2-\(\frac{3}{2}\)
x =\(\frac{1}{2}\)
\(\left(x+\frac{3}{2}\right)^2=4\)
\(\left(x+\frac{3}{2}\right)^2=2^2\)
\(\Rightarrow x+\frac{3}{2}=2\)
\(x=2-\frac{3}{2}\)
\(x=\frac{1}{2}\)
(x+3/2)^2=4 <=> (x+3/2)^2=(+-2)^2 =>x+3/2=2 hoac x+3/2=-2
=>x=1/2 hoac x=-7/2
\(\left(x+\frac{3}{2}\right)^2=4\Leftrightarrow\left(x+\frac{3}{2}\right)^2=2^2\)
\(\Rightarrow\hept{\begin{cases}x+\frac{3}{2}=2\\x+\frac{3}{2}=-2\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{1}{2}\\x=\frac{-7}{2}\end{cases}}\)
\(\text{Vậy x}\varepsilon\left\{\frac{1}{2};\frac{-7}{2}\right\}\)