Question

\(|x+\dfrac{3}{4}|-0,75=\dfrac{1}{3}\)

Answer 1

\(\left|x+\dfrac{3}{4}\right|-0,75=\dfrac{1}{3}\)

\(\Rightarrow\left|x+\dfrac{3}{4}\right|-\dfrac{3}{4}=\dfrac{1}{3}\)

\(\Rightarrow\left|x+\dfrac{3}{4}\right|=\dfrac{13}{12}\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=\dfrac{13}{12}\\x+\dfrac{3}{4}=-\dfrac{13}{12}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-\dfrac{11}{6}\end{matrix}\right.\)

Answer 2

\(\left|x+\dfrac{3}{4}\right|-0,75=\dfrac{1}{3}\\ \left|x+\dfrac{3}{4}\right|-\dfrac{3}{4}=\dfrac{1}{3}\\ \left|x+\dfrac{3}{4}\right|=\dfrac{1}{3}+\dfrac{3}{4}\\ \left|x+\dfrac{3}{4}\right|=\dfrac{13}{12}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=\dfrac{13}{12}\\x+\dfrac{3}{4}=-\dfrac{13}{12}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-\dfrac{22}{12}=-\dfrac{11}{6}\end{matrix}\right.\)