Question

/x+\(\dfrac{2}{3}\)/-/x-7/=\(\dfrac{5}{3}\)

x=?

Answer 1

\(x+\dfrac{2}{3}=0=>x=\dfrac{-2}{3}\) và \(x-7=0=>x=7\)

=> các th x≤ -2/3 hoặc - 2/3 < x<7 hoặc x ≥7

TH1 => \(-\dfrac{2}{3}-x-\left(7-x\right)=\dfrac{5}{3}\)

=> 0x=\(\dfrac{28}{3}\) ktm 

TH2 -2/3<x<7

=> \(\dfrac{2}{3}+x-\left(7-x\right)=\dfrac{5}{3}\)

2x=8

=>x=4 tm

TH3 x≥7

\(x+\dfrac{2}{3}-x+7=\dfrac{5}{3}\)

=> 0x=-6 tkm