Ta có: \(y=0,75=\dfrac{3}{4}=\dfrac{15}{20}\Rightarrow\dfrac{17}{20}>\dfrac{15}{20}\)
Vậy x > y
Ta có: \(y=0,75=\dfrac{3}{4}=\dfrac{15}{20}\Rightarrow\dfrac{17}{20}>\dfrac{15}{20}\)
Vậy x > y
so sánh
\(x=-2\dfrac{1}{5}vày=\dfrac{110}{-50}\)
Tìm x, biết:
a) \(\dfrac{1}{20}\) - (x - \(\dfrac{8}{5}\)) = \(\dfrac{1}{10}\)
b) \(\dfrac{7}{4}\) - (x + \(\dfrac{5}{3}\)) = \(\dfrac{-12}{5}\)
c) x - [\(\dfrac{17}{2}\) - \(\left(\dfrac{-3}{7}+\dfrac{5}{3}\right)\)] = \(\dfrac{-1}{3}\)
\(\dfrac{-11}{31}\cdot\dfrac{-2}{17}+\dfrac{7}{31}\cdot\dfrac{-20}{17}-\dfrac{9}{17}\cdot\dfrac{11}{31}\)
Tìm x:
a) \(-\dfrac{3}{5}\) - x = -0,75
b) \(1\dfrac{4}{5}\) = -0,15 - x
c) x + \(\dfrac{1}{3}\) = \(\dfrac{2}{5}\) - ( \(-\dfrac{1}{3}\) )
\(\left(-0,75.x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=\dfrac{-5}{6}\)
Tìm x : \(\dfrac{1}{2}-\left|2-3x\right|=\sqrt{\dfrac{19}{16}}-\sqrt{\left(-0,75\right)^2}\)
HELP ME!
\(A=\left(\dfrac{-40}{51}.0.32.\dfrac{17}{20}\right):\dfrac{64}{75}\)
\(\dfrac{-10}{13}\)+\(\dfrac{5}{7}\)-\(\dfrac{3}{13}\)+\(\dfrac{2}{17}\)-\(\dfrac{11}{20}\)
( làm chi tiết )
\(-2\frac{1}{5}\&\frac{110}{-50};\frac{17}{20}\&0,75\)
so sánh số hữu tỉ giúp mk vs