Các câu hỏi tương tự
\(\hept{\begin{cases}x+my=m+1\left(1\right)\\mx+y=3m-1\left(2\right)\end{cases}}\)
tim m de he phuong trinh co nghiem duy nhat (x;y) sao cho x;y co gia tri nho nhat
Cho he phuong trinh sau:
\(\hept{\begin{cases}\left(m+1\right)x+my=2m-1\\mx-y=m^2-2\end{cases}}\)
Tim m de he phuong trinh co nghiem duy nhat (x;y) thoa man P= xy dat gia tri lon nhat.
cho he phuong trinh\(\hept{\begin{cases}mx-t=2m\\x-my=1+m\end{cases}}\)
a.giai hpt khi m=-2
b.tim m de hpt co nghiem duy nhat.tim nghiem duy nhat do.
c.chung to M(x,y) luon thuoc 1 duong thang co dinh voi (x,y)la nghiem tim dc o cau b.
Giai he phuong trinh:
a) \(\hept{\begin{cases}\left(x+y\right).\left(y+z\right)=187\\\left(y+z\right).\left(z+x\right)=154\\\left(z+x\right).\left(x+y\right)=238\end{cases}}\)
b) \(\hept{\begin{cases}x^2-y^2=1\\4x^2-5xy=2\end{cases}}\)
Giai he phuong trinh
1) \(\hept{\begin{cases}\left(x^4+1\right)\left(y^4+1\right)=4xy\\\sqrt[3]{x-1}-\sqrt{y-1}=1-x^3\end{cases}}\)
2) \(\hept{\begin{cases}\left(x+\sqrt{x^2+2012}\right)\left(y+\sqrt{y^2+2012}\right)=2012\\x^2+z^2-4\left(y+z\right)+8=0\end{cases}}\)
cho he phuong trinh\(\hept{\begin{cases}x-2y=3-m\\2x+y=3\left(m+2\right)\end{cases}}\)tim m de \(x^2+y^2\)dat GTNN
giai he phuong trinh sau:\(\hept{\begin{cases}\frac{2x-3}{2y-5}=\frac{3x+1}{3y-4}\\2\left(x-3\right)-3\left(y+2\right)=-16\end{cases}}\)
11 tháng 3 2018 lúc 22:49
hept{begin{cases}left(m-1right)x-my3m-12x-left(m+3right)yend{cases}Leftrightarrowhept{begin{cases}left(m-1right)x-mleft(2x-left(m+3right)right)3m-12x-left(m+3right)yend{cases}}}Leftrightarrowhept{begin{cases}left(m-1right)x-2mx+mleft(m+3right)3my2x-left(m+3right)end{cases}}Leftrightarrowhept{begin{cases}xleft(-m-1right)-m^2-2my2x-left(m+3right)end{cases}}Leftrightarrowhept{begin{cases}xleft(m+1right)left(m+1right)^2y2x-left(m+3right)end{cases}Leftrightarrowhept{begin{cases}xm+1Rightarrow ym-3m-1...
Đọc tiếp
\(\hept{\begin{cases}\left(m-1\right)x-my=3m-1\\2x-\left(m+3\right)=y\end{cases}\Leftrightarrow\hept{\begin{cases}\left(m-1\right)x-m\left(2x-\left(m+3\right)\right)=3m-1\\2x-\left(m+3\right)=y\end{cases}}}\)
\(\Leftrightarrow\hept{\begin{cases}\left(m-1\right)x-2mx+m\left(m+3\right)=3m\\y=2x-\left(m+3\right)\end{cases}}\Leftrightarrow\hept{\begin{cases}x\left(-m-1\right)=-m^2-2m\\y=2x-\left(m+3\right)\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x\left(m+1\right)=\left(m+1\right)^2\\y=2x-\left(m+3\right)\end{cases}\Leftrightarrow\hept{\begin{cases}x=m+1\Rightarrow y=m-3\\m=-1\Rightarrow x;y\left(\text{loai}\right)\end{cases}}}\)
\(\Rightarrow\hept{\begin{cases}x=m+1\\y=m-3\end{cases}}\)
\(\Rightarrow x^2+y^2< 4\Leftrightarrow\left(m+1\right)^2-\left(m-3\right)^2< 4\)
\(\Leftrightarrow8m< 12\)
\(\Leftrightarrow m< 3/2\)
*P/s: T trả đấy!*
Định m để HPT có nghiêm
1.\(\hept{\begin{cases}m\left(m-1\right)x+m\left(m+1\right)y=m^3+2\\\left(m^2-1\right)x+\left(m^3+1\right)y=m^4-1\end{cases}}\)
2.\(\hept{\begin{cases}\left(m+3\right)x+\left(m-3\right)y=2m\\\left(m^2+9\right)+\left(m^2-9\right)y=2m^2\end{cases}}\)
Mình cần gấp lắm!!!Cứu với