\(\frac{x^7}{81}\) = 27
x7 : 81 = 27
x7 = 27 . 81 = 33 . 34
x7 = 37
Suy ra : x = 3
Bài 2 :
\(\frac{x^8}{9}\) = 729
x8 : 9 = 729
x8 = 729 . 9
x8 = 36 . 32
x8 = 38
Suy ra : x = 3
Tìm X biết : x^7/81 = 27. x^8/9 = 729
Tìm x,biết:
a) \(\frac{x^7}{81}\) = 27
b) \(\frac{x^8}{9}\) 729
1, Tìm x
a, (2^x)^5 : 4^3 = 8^15
b, (3^2)^x . 9^3 = 243^9
c, ( 1/125)^3 . 5^x = 25^5
d, 1/81: 3^x = 1/729
e, ( 5x-2)^4 = 16^8
Tìm x biết:
a,\(\frac{x^7}{81}=27\) b,\(\frac{x^8}{9}=729\)
tìm x biết : a,\(\frac{x^7}{81}=27\); b,\(\frac{x^8}{9}=729\); c.\(^{\left[x-\frac{1}{2}\right]^0}\); d,\(\left[X-2\right]^2=1\); e, \(\left[2X-1\right]^3=8\); f,\(\left[X+\frac{1}{2}\right]^2\)=\(\frac{1}{16}\)
1.Tìm x
a)(1/4) mũ x :1/16=1/4
b)81 mũ x:9 mũ x=729
giúp mk nha!Thanks nhìu
1. Tìm x\(\inℚ\), biết:
a)\(\left(x-\frac{1}{2}\right)2=0\)
b)\(\left(x-2\right)^2=1\)
c) \(\left(2x-1\right)^3=-8\)
d)\(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
e)\(\frac{x^7}{81}=27\)
g)\(\frac{x^8}{9}=^{729}\)
Tìm x sao cho x^8/9=729
